SOLUTION: find three consecutive positive integers such that the product of the first and third one is less than six times the second

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: find three consecutive positive integers such that the product of the first and third one is less than six times the second      Log On


   

Question 849385: find three consecutive positive integers such that the product of the first and third one is less than six times the second
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive integers: (x-1), x, (x+1)

(x-1)(x+1) < 6x
x^2 - 1 < 6x
x^2 - 6x - 1 < 0

integer solutions of x: x = 0, 1, 2, 3, 4

sets of integers: (1, 2, 3), (2, 3, 4), (3, 4, 5) --- only listed ones that were positive