SOLUTION: This quadriatic problems just get to me and looking for an area is even more confusing.
The question the teacher asks, not in the textbook is this:
1. You have 188 feet of
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: This quadriatic problems just get to me and looking for an area is even more confusing.
The question the teacher asks, not in the textbook is this:
1. You have 188 feet of
Log On
Question 84913This question is from textbook
: This quadriatic problems just get to me and looking for an area is even more confusing.
The question the teacher asks, not in the textbook is this:
1. You have 188 feet of fencing to enclose a rectangular region. What is the maximum area? This question is from textbook
You can put this solution on YOUR website! the perimeter (2L+2W) of the fence is 188, so L+W=94 ... and W=94-L ... so the area (L*W) is also L(94-L) or 94L-L^2
A=94L-L^2 is a downward opening parabola ... the maximum value for A lies on the axis of symmetry
the general equation for the axis of symmetry is x=-b/2a or in this case L=-94/-2 or L=47
