SOLUTION: Solve the trigonometric equation, using exact values when possible, where x is a real number such that 0 is less than or equal to x and less than 2pi.
2sin^2(x) - 6sin(x) - 3 =
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-> SOLUTION: Solve the trigonometric equation, using exact values when possible, where x is a real number such that 0 is less than or equal to x and less than 2pi.
2sin^2(x) - 6sin(x) - 3 =
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Question 84904: Solve the trigonometric equation, using exact values when possible, where x is a real number such that 0 is less than or equal to x and less than 2pi.
2sin^2(x) - 6sin(x) - 3 = 0 Answer by jim_thompson5910(35256) (Show Source):
Quadratic equation (in our case ) has the following solutons:
For these solutions to exist, the discriminant should not be a negative number.
First, we need to compute the discriminant : .
Discriminant d=60 is greater than zero. That means that there are two solutions: .
Quadratic expression can be factored:
Again, the answer is: 3.43649167310371, -0.436491673103709.
Here's your graph:
Since these values are irrational, we cannot use exact values. So we have 2 intermediate answers
or
which means
or
For each case, take the arcsine of both sides
or
taking the arcsine of the first answer, we get
or
remember there are 2 answers when taking the arcsine
Since the domain of arcsine is we cannot take the arcsine of 3.436. So taking the arcsine of the second answer, we get