SOLUTION: (1) A drawer contains 41 cents and 7 cents stamps. The number of 41 cents stamps is four less than three times the number of 7 cents stamps. The total value of all the stamps is $4

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: (1) A drawer contains 41 cents and 7 cents stamps. The number of 41 cents stamps is four less than three times the number of 7 cents stamps. The total value of all the stamps is $4      Log On


   

Question 848827: (1) A drawer contains 41 cents and 7 cents stamps. The number of 41 cents stamps is four less than three times the number of 7 cents stamps. The total value of all the stamps is $4.86. How many 41 cents stamps are in the drawer?
Equation:
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Answer by CubeyThePenguin(3113) About Me  (Show Source):
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x = number of 41 cent stamps
y = number of 7 cent stamps

x = 3y - 4
41x + 7y = 486

Substitute the first equation into the second.

41(3y - 4) + 7y = 486
123y - 164 + 7y = 486
130y = 650
y = 5

There are 5 7-cent stamps and 11 41-cent stamps.