SOLUTION: I am helping my daughter do her homework and we are stuck on this question, we are missing a step.
The area of a table is 44 sq ft, and twice the length is 5 feet shorter than 2
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The area of a table is 44 sq ft, and twice the length is 5 feet shorter than 2
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Question 848560: I am helping my daughter do her homework and we are stuck on this question, we are missing a step.
The area of a table is 44 sq ft, and twice the length is 5 feet shorter than 2 times the width. Find the perimeter of the top.
Many thanks,
You can put this solution on YOUR website! The area of a table is 44 sq ft, and twice the length is 5 feet shorter than 2 times the width. Find the perimeter of the top.
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L*W = 44 (the area)
2L + 5 = 2W (length and width deal)
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L = 44/W
2L + 5 = 2W
sub for L
88/W + 5 = 2W
88 + 5W = 2W^2
2W^2 - 5W - 88 = 0
(W - 8)*(2W + 11) = 0
W = 8 ft
L = 5.5 ft
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P = 2W + 2L = 27 feet
You can put this solution on YOUR website! One MUST assign variables.
w=width
L=Length ------direct translation from description ------direct translation from description
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Capital L was chosen for easier reading in order to not confuse digit one with lower-case L.
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Using area, w=44/L.
Substituting into dimensions equation, ; .
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Guessing that the quadratic is not factorable, use general solution.
Discriminant, 5*5-4*2(-88)=25+8*8*11=25+11*64=25+704=729 , we must use the positive square root form. , which is same as 5.5 feet or 5 feet 6 inches. , 8 feet.
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