SOLUTION: The area of a rectangular lot is to be 1456 square ft. if the width of the lot is 24ft less than the length, find the dimensions of the lot.

Algebra ->  Surface-area -> SOLUTION: The area of a rectangular lot is to be 1456 square ft. if the width of the lot is 24ft less than the length, find the dimensions of the lot.      Log On


   

Question 848524: The area of a rectangular lot is to be 1456 square ft. if the width of the lot is 24ft less than the length, find the dimensions of the lot.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Let x represent the length

 x(x-24) = 1456

 x^2 - 24x - 1456 = 0

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ 

x+=+%2824+%2B-+sqrt%28+6400+%29%29%2F%282%29+ 

x+=+12+%2B-+40+    (Tossing out the negative solution for unit measure)

 x = 52t, the length.  The width is 28ft

dimensions of the lot: 52ft by 28ft

CHECKING our answer***

52ft*28ft = 1456ft^2

Wish You the Best in your Studies.