You can put this solution on YOUR website! x+y>90
x*y<1800
x > 90 -y
y*(90-y) < 1800
90y - y^2 < 1800
y^2 -90y +1800 > 0
(y-30)(y-60) > 0
y<30 y>60
x>60 x<30
So we just need two numbers of which one is less than 30 and the other is greater than 60.
Let's try 29 and 62
29 + 62 = 91>90
29*61 = 1798 < 1800