SOLUTION: Solve the exponential equation 2^3X=4^Xplus 1

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Question 848338: Solve the exponential equation 2^3X=4^Xplus 1
Answer by swincher4391(1107) About Me  (Show Source):
You can put this solution on YOUR website!
2%5E%283x%29+=+4%5E%28x%2B1%29
2%5E%283x%29+=+%282%5E2%29%5E%28x%2B1%29
2%5E%283x%29+=+2%5E%282%28x%2B1%29%29
2%5E%283x%29+=+2%5E%282x%2B2%29
take log base 2 of both sides
3x+=+2x%2B2
x+=+2