SOLUTION: A rectangle has a length of x. It's width is 3 feet longer than twice the length. Find the dimensions if its area is 80 feet squared.

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Question 848331: A rectangle has a length of x. It's width is 3 feet longer than twice the length. Find the dimensions if its area is 80 feet squared.
Answer by swincher4391(1107) About Me  (Show Source):
You can put this solution on YOUR website!
x(2x+3) = 80
2x^2 + 3x - 80 = 0
using the quadratic formula we get
x=%28sqrt%28649%29-3%29%2F4 = 5.62ft
2(5.62)+ 3 = 14.24
5.62 x 14.24