SOLUTION: Jill has a swimming pool in her backyard. It is shaped like a rectangle, and measures approximately 19.7 feet wide and 29.5 feet long. It is an average of 5 feet deep. During a few
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-> SOLUTION: Jill has a swimming pool in her backyard. It is shaped like a rectangle, and measures approximately 19.7 feet wide and 29.5 feet long. It is an average of 5 feet deep. During a few
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Question 848009: Jill has a swimming pool in her backyard. It is shaped like a rectangle, and measures approximately 19.7 feet wide and 29.5 feet long. It is an average of 5 feet deep. During a few hot weeks during the summer, some water evaporates from the pool, and Jill needs to add 10 inches of water to the depth of the pool, using her garden hose. Although her water pressure varies, the water flows through Jill’s garden hose at an average rate of 10 gallons/minute.
1. Convert all measurements to metric units (meters, cubic meters, and liters).
2.How much water (how many liters) will Jill need to add to her pool to return the water level to its original depth? How many gallons of water is this?
3.How long will Jill need to run the hose?
You can put this solution on YOUR website! The volume that needs to be filled is
(19.7 ft)*(29.5 ft)*(10/12 ft)
Convert measurements to cm. We will be
using the fact that 1000 cm = 1 liter a bit later.
19.7 ft = 19.7*(30.48) = 600.456 cm
29.5 ft = 29.5*(30.48) = 899.16 cm
10/12 ft = (10/12)*(30.48) = 25.4 cm
So the volume to be filled is
(600.456)*(899.16)*(25.4) = .
Since 1 liter =
we have
Since water flows at 10 gal/min, this is
10*(3.78541178) liters / minute
37.8541178 liters/minute
Dividing by 37.8541178 liters/minute
will tell us the number of minutes to top out the pool. = 362.375 minutes or just
over 6 hours.
1.3713612830784 * 10^4 liters in gallons is
(1.3713612830784) * 10^4 *(0.264172) = 3622.75 gallons
At 10 gallons per minute it takes 3622.75/10 = 362.275 minutes or just over
six hours.
