SOLUTION: how many ounces of pure silver that cost $8.50 an ounce must be mixed with 100 oz of a silver alloy that cost $5.00 an ounce to make an alloy that cost $6.50 an ounce.

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: how many ounces of pure silver that cost $8.50 an ounce must be mixed with 100 oz of a silver alloy that cost $5.00 an ounce to make an alloy that cost $6.50 an ounce.      Log On


   

Question 847979: how many ounces of pure silver that cost $8.50 an ounce must be mixed with 100 oz of a silver alloy that cost $5.00 an ounce to make an alloy that cost $6.50 an ounce.
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
Let z = the ounces of silver to add.

%288.50z%2B5%2A100%29%2F%28z%2B100%29=6.50

See the lesson, http://www.algebra.com/tutors/Two-Part-Mixture-with-one-material-quantity-unknown.lesson?content_action=show_dev