Question 847473: Determine the probability of any one outcome
n = 5, x = 2, p = 0.646
n = 11, x = 9, p = 0.42
Answer by swincher4391(1107)   (Show Source):
You can put this solution on YOUR website! This is the binomial distribution and basically all that is happening is that you are choosing x successes out of n total trials. Since all are independent, we can just multiply the resulting probabilities. The other trials [n-x trials] that are failures are counted as 1-p. So, to summarize, out of x chosen successes out of n, we multiply the probability of success x times, and the probability of failure the other n-x times.
So in general we have the formula (n choose x) * (p)^x * (q)^(n-x) where q = 1-p
1.
(5 choose 2) * (.646)^2 * (1-.646)^3 = .1851
2.
(11 choose 9) * (.42)^9 * (1-.42)^2 = .0075
|
|
|
