Question 847202: Two dice are thrown once. Find the probability of getting a multiple of 3 on the first die or a total of 8.
Answer by swincher4391(1107)   (Show Source):
You can put this solution on YOUR website! P[multiple of 3 on the first die] = 1/3
ways to get a total of 8:
(2,6)
(3,5)
(4,4)
(5,3)
(6,2)
So 5/36 ways to sum to 8.
Notice that our roll of (3,5) is being counted in both cases so we must subtract it once.
Putting it all together:
P[multiple of 3 on first, sum to 8] = 1/3 + 5/36 - 1/36 = 4/9
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