SOLUTION: A restaurant sold a total of 418 large and small hamurgers during one day. Total hamburger sales were $1077. Large hamburgers sold for $3, and small hamburgers sold for $1.50. Find
Question 847031: A restaurant sold a total of 418 large and small hamurgers during one day. Total hamburger sales were $1077. Large hamburgers sold for $3, and small hamburgers sold for $1.50. Find how many small hamburgers (s) and large hamburgers (L) were sold.
So far, I have:
L+s=418
3L+1.50s=1077
3L would then become 2s because it is double the price of a small hamburger.
2s+1.50s=1077
Total price of large hamburgers sold= $718
Total of small= $359
I then tried dividing 718 by 3 and 359 by 1.50 but the numbers aren't adding up.
I don't know what I did wrong and I don't know how to find the solution.
Thank you in advance (: Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! "3L would then become 2s because it is double the price of a small hamburger"
No! You're mixing apples and oranges.
The price difference is captured in the 3 and 1.5.
1.
2.
From eq. 1,
Substitute into eq. 2,
Then,
