SOLUTION: STACEY HAS A COLLECTION OF COINS FROM 5 DIFFERENT COUNTRIES. HALF FROM ENGLAND, 1/6 FROM SWITZERLAND, 1/6 FROM FRANCE, 1/12 FROM ITALY AND 7 FROM SPAIN. HOW MANY COINS AREIN THE CO

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: STACEY HAS A COLLECTION OF COINS FROM 5 DIFFERENT COUNTRIES. HALF FROM ENGLAND, 1/6 FROM SWITZERLAND, 1/6 FROM FRANCE, 1/12 FROM ITALY AND 7 FROM SPAIN. HOW MANY COINS AREIN THE CO      Log On

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Question 846788: STACEY HAS A COLLECTION OF COINS FROM 5 DIFFERENT COUNTRIES. HALF FROM ENGLAND, 1/6 FROM SWITZERLAND, 1/6 FROM FRANCE, 1/12 FROM ITALY AND 7 FROM SPAIN. HOW MANY COINS AREIN THE COLLECTION AND HOW MANY FROM EACH COUNTRY?

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = the total number of coins
+%281%2F2%29%2Ax+%2B+%281%2F6%29%2Ax+%2B+%281%2F6%29%2Ax+%2B+%281%2F12%29%2Ax+%2B+7+=+x+
Multiply both sides by +12+
+6x+%2B+2x+%2B+2x+%2B+x+%2B+84+=+12x+
+11x+%2B+84+=+12x+
+x+=+84+
There are 84 coins
+%281%2F2%29%2A84+=+42+ from England
+%281%2F6%29%2A84+=+14+ from Switzerland
+%281%2F6%29%2A84+=+14+ from France
+%281%2F12%29%2A84+=+7+ from Italy
+7+ from Spain
--------------------
+42+%2B+14+%2B+14+%2B+7+%2B+7+=+84+
OK