Question 846784: Hi there, I really appreciate your help!
Of 300 male and 300 female employees at the Flagstaff Mall, 180 of the men and 220 of the women are on flex-time (flexible working hours). Given that an employee selected at random from this group is on flex-time, what is the probability that the employee is a woman?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Hi there, I really appreciate your help!
Of 300 male and 300 female employees at the Flagstaff Mall, 180 of the men and 220 of the women are on flex-time (flexible working hours).
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Given that an employee selected at random from this group is on flex-time, what is the probability that the employee is a woman?
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P(woman | flex time) = P(woman AND flextime)/P(flextime)
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= [P(flex |woman)*P(woman)]/P(flextime)
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= [(220/300)*(0.5)]/(400/600) = 0.55
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Cheers,
Stan H.
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