SOLUTION: A train leaves a station at noon traveling north at an average speed of 30 mph. A second train leaves the same station at 3:00 P.M. and travels south at 45 mph. At what time

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Question 846615: A train leaves a station at noon traveling north at an average speed of 30 mph.
A second train leaves the same station at 3:00 P.M. and travels south at 45 mph.
At what time will the trains be 500 miles apart?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
D1=30%2A%28T%2B3%29
D2=45%2AT
where T is zero at 3:00.
Find T when D=500.
D=D1%2BD2
30%2A%28T%2B3%29%2B45%2AT=500
30T%2B90%2B45=500
30T=365
T=365%2F30=73%2F6=12%2B1%2F6hours
1/6 hour = 10 minutes.
SInce time was zero at 3:00 PM, the trains will be 500 miles apart at 3:10AM.