Question 84653: You are choosing the batting order for a team with 13 players. How many different ways can you choose 9 players for the batting order?
Answer by rapaljer(4671)   (Show Source):
You can put this solution on YOUR website! Combinations and permutations really give students a hard time. First of all, with combinations, the ORDER does NOT matter. With permutations, the ORDER DOES matter!! In this case, what you are trying to count is the number of ways to arrange a batting ORDER!! Obviously, the ORDER matters, so this is a permutation.
You must choose a batting order choosing 9 people out of 13 players. This is a permutation of 13, taking 9 at a time. You could write this as
P(13,9). Most calculators will do this for you if you know how to enter it in the calculator. If you don't know how to do this, you can always calculate it yourself, by making 9 blank spaces in a product as follows:
P(13,9) = ___*___*___*___*___*___*___*___*___
Then start with 13, and count down, filling all the 9 spaces.
P(13,9) = 13*12*11*10*9*8*7*6*5=259,459,200.
R^2 at SCC
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