SOLUTION: Find three consecutive positive even integers such that the product of the second and third integers is twenty more then ten times the first integer. Solve with an algebraic soluti

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Question 846320: Find three consecutive positive even integers such that the product of the second and third integers is twenty more then ten times the first integer. Solve with an algebraic solution
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive even integers: (x-2), x, (x+2)

x(x+2) = 20 + 10(x-2)
x^2 + 2x = 10x
x^2 - 8x = 0
x(x - 8) = 0

x is positive, so the integers are 6, 8, and 10.