Question 845490: if a square is drawn on the longer side of a rectangle ,the square area is 100% greater than the rectangle area, but if another square is drawn on the shorter side the square is 50% smaller.Given that the difference in areas of the two squares is 12cm^2.Find the dimensions of the original rectangle.
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! if a square is drawn on the longer side of a rectangle ,the square area is 100% greater than the rectangle area, but if another square is drawn on the shorter side the square is 50% smaller.Given that the difference in areas of the two squares is 12cm^2.Find the dimensions of the original rectangle.
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Let rectangle area be "A"::
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Equation:
L^2 = 2A
S^2 = 0.5A
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2A-0.5A = 12 cm^2
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(3/2)A = 12 cm^2
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A = 8 cm^2
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Cheers,
Stan H.
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