SOLUTION: I need help to fully factor this problem: 3 * (2x-1)^2 * (2) * (x+3)^1/2 + (2x-1)^3 * (1/2) * (x+3)^-1/2 On the assumption that I started out correctly, I'm simply stuck with t

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I need help to fully factor this problem: 3 * (2x-1)^2 * (2) * (x+3)^1/2 + (2x-1)^3 * (1/2) * (x+3)^-1/2 On the assumption that I started out correctly, I'm simply stuck with t      Log On


   

Question 84544This question is from textbook Precalculus, Mathematics for Calculus
: I need help to fully factor this problem:
3 * (2x-1)^2 * (2) * (x+3)^1/2 + (2x-1)^3 * (1/2) * (x+3)^-1/2
On the assumption that I started out correctly, I'm simply stuck with the expression as it is below:
(24x^2 - 24x + 6) * (x+3)^1/2 + (4x^3 - 6x^2 + 2x + x - 1/2) * (x+3)^-1/2
Any help at with this would be great! This question is from textbook Precalculus, Mathematics for Calculus

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
I need help to fully factor this problem:
3 * (2x-1)^2 * (2) * (x+3)^1/2 + (2x-1)^3 * (1/2) * (x+3)^-1/2
You're expanding, not factoring. When you factor, you take out the lowest powers of what each term has in common:



%281%2F2%29%282x-1%29%5E2%28x%2B3%29%5E%28-1%2F2%29%2812x%2B36%2B2x-1%29
%281%2F2%29%282x-1%29%5E2%28x%2B3%29%5E%28-1%2F2%29%2814x%2B35%29
%281%2F2%29%282x-1%29%5E2%28x%2B3%29%5E%28-1%2F2%29%2A7%282x%2B5%29
highlight%28%287%2F2%29%282x-1%29%5E2%28x%2B3%29%5E%28-1%2F2%29%282x%2B5%29%29
That was a good one!!!
Happy Calculating!!!!