SOLUTION: The perimeter of a rectangular field is 628 meters . The length is 6 more than the width . Set up a system of equations and solve to find the length and width

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Question 845382: The perimeter of a rectangular field is 628 meters . The length is 6 more than the width . Set up a system of equations and solve to find the length and width
Answer by josgarithmetic(39632) About Me  (Show Source):
You can put this solution on YOUR website!
This kind of question seems so common. What if you generally had:
'
The perimeter of a rectangle is p meters . The length is k more than the width . Set up a system of equations and solve to find the length and width.

Let L = length
Let w = width
Perimeter information gives 2L%2B2w=p.
Other description gives L=k%2Bw.

Those are the equations for the system having L and w as variables, UNKNOWN variables. Sometimes one equation or the other could use refinement or simplification before using a final form of the system of equations.

Often the choice for which method to solve the system is the student's. The general system shown above can easily be handled through substituting for L in the perimeter equation, and then solve for w. ...
An alternative can be, substitute for w in one of the equations.
Another alternative is, depending on simplifications made, use the system as:
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2L+2w=p
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L-w=k
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and use Elimination Method.