SOLUTION: Find three consecutive odd integers such that three times the middle number is 23 more than the sum of the othe two.
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Question 845101
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Find three consecutive odd integers such that three times the middle number is 23 more than the sum of the othe two.
Answer by
CubeyThePenguin(3113)
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consecutive odd integers: (x-2), x, (x+2)
3x = 23 + (x-2) + (x+2)
3x = 2x + 23
x = 23
The integers are 21, 23, and 25.
