SOLUTION: suppose that Maria has a hundred and fifty coins consisting of pennies nickels and dimes the number of nickels she has is 10 less then twice the number of pennies the number of Dim

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Question 844989: suppose that Maria has a hundred and fifty coins consisting of pennies nickels and dimes the number of nickels she has is 10 less then twice the number of pennies the number of Dimes she has is 20 less than three times the number of pennies how many coins of each kind does she have
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
number of nickels she has is 10 less then twice the number of pennies+highlight_green%28x%29
the number of Dimes she has is 20 less than three times the number of pennies+highlight_green%28x%29
Question states***Maria has a hundred and fifty coins
x + (2x-10) + (3x-20) = 150
6x = 180
x = 30, the number of pennies. 50 nickels and 70 dimes
CHECKING our answer***
30 + 50 + 70 = 150 coins
Wish You the Best in your Studies.