SOLUTION: Factor completely. y^4 + 3y^3 – 5y^2 – 15y The answer I ended up with is y(y^2 – 5)(y + 3)

Algebra ->  Equations -> SOLUTION: Factor completely. y^4 + 3y^3 – 5y^2 – 15y The answer I ended up with is y(y^2 – 5)(y + 3)      Log On


   

Question 84492: Factor completely. y^4 + 3y^3 – 5y^2 – 15y
The answer I ended up with is y(y^2 – 5)(y + 3)
Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
Your answer is correct for this one also. You're doing great!