SOLUTION: Determine whether SQRT25/68 is rational or irrational. I came up with Irrational. Did I just maybe get it right?

Algebra ->  Equations -> SOLUTION: Determine whether SQRT25/68 is rational or irrational. I came up with Irrational. Did I just maybe get it right?      Log On


   

Question 84483: Determine whether SQRT25/68 is rational or irrational.
I came up with Irrational.
Did I just maybe get it right?
Found 2 solutions by checkley75, rapaljer:
Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
SQRT(25/68)
SQRT(5*5/4*17)
5/2SQRT(1/17)
THIS IS A RATIONAL NUMBER.
AN IRRATIONAL NUMBER IS ONE WITH A NEGATIVE UNDER THE SQRT SIGN THUS:
SQRT(-16)=4i

Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
The answer you were given to this problem by Checkley is WRONG! YOU WERE CORRECT in saying that this is an irrational number. An irrational number is a REAL NUMBER, but it is one that is NOT rational. That is, it CANNOT be expressed as a quotient of two integers. Irrational numbers include radical expressions that do not come out even, such as sqrt%282%29, sqrt%283%29+, etc. If the square root happens to be of a perfect square, such as sqrt%2825%29+, then it is considered to be rational. Your answer involves the square root of a number, 68, that is not a perfect square. Therefore it is an irrational number.

sqrt%2825%2F68%29 is a REAL but yet an IRRATIONAL NUMBER.

R^2 at SCC