SOLUTION: how do you write 9x^2+4y^2+18x-32y-71=0 in standard form ?

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Question 844629: how do you write 9x^2+4y^2+18x-32y-71=0 in standard form ?
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
how do you write 9x^2+4y^2+18x-32y-71=0 in standard form ?
9x^2+18x+4y^2-32y-71=0
complete the square:
9(x^2+2x+1)+4(y^2-8y+16)=71+9+64
9(x+1)^2+4(y-4)^2=144
%28x%2B1%29%5E2%2F16%2B%28y-4%29%5E2%2F36=1
This is an equation of an ellipse with vertical major axis and center at (-1,4)
Its standard form%28x-h%29%5E2%2Fb%5E2%2B%28y-k%29%5E2%2Fa%5E2=1, a>b, (h,k)=(x,y) coordinates of center.