SOLUTION: Suppose that the amount of time teenagers spend on the internet per week is normally distributed with a standard deviation of 1.5 hours. A sample of 100 teenagers is selected at ra

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Question 844304: Suppose that the amount of time teenagers spend on the internet per week is normally distributed with a standard deviation of 1.5 hours. A sample of 100 teenagers is selected at random, and the sample mean computed as 6.5 hours. Determine and interpret the 99% confidence interval estimate of the population mean.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
ME = 2.576%2A1.5%2Fsqrt%28100%29+=+.3864
6.5 - ME< mu < 6.5 + ME
Note:
80% z = 1.28155
90% z =1.645
92% z = 1.751
95% z = 1.96
98% z = 2.326
99% z = 2.576