Hi,
using a TI Calculator
The syntax is normalcdf(smaller, larger, µ, σ)
mean age normalcdf(73, 9999, 75,6)= .6305 0r 63.05%
Note: The 9999 is used as the larger value to be at least 5 standard deviations from the mean.
Or z = 
P(z≤ -1/3) = .3695 and 1 - .3695 = .6305