Since a,b,c are in harmonic progression, their
reciprocals ,, form an arithmetic sequence:
Let d be the common difference. Then
Solve each for d
Since both equal d, they are equal to each other:
Multiply through by LCD of abc
ac - bc = ab - ac
2ac = ab + bc
And since we are given that
ab + bc + ca = 15
We can substitute 2ac for ab + bc and get
2ac + ca = 15
And since ac is the same as ca
2ca + ca = 15
3ca = 15
ca = 5
Edwin