SOLUTION: solve each by completing the square 2x^2+10x+11=0

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Question 84422: solve each by completing the square
2x^2+10x+11=0

Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
Given:
.
2x%5E2%2B10x%2B11=0
.
Subtract 11 from both sides to get the constant on the right side of the equation. This results
in the equation becoming:
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2x%5E2+%2B+10x+=+-11
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You want the multiplier (coefficient) of the x%5E2 term to be 1. To make that happen,
divide every term on both sides of the equation by the multiplier of the x%5E2 which is 2.
When you do that division the equation becomes:
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x%5E2+%2B+5x+=+-11%2F2
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Next, divide the multiplier of the x term by 2. That is divide the 5 by 2 to get 5%2F2.
Square that term to get 25%2F4. Now add 25%2F4 to both sides of the equation.
You get:
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x%5E2+%2B+5x+%2B+25%2F4+=+-11%2F2+%2B+25%2F4
.
The left side factors to:
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%28x%2B%285%2F2%29%29%5E2+=+-11%2F2+%2B+25%2F4
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Multiply the -11%2F2 by 2%2F2 to get -22%2F4 which now has a common denominator
with the other term on the right side. Substitute this into the equation to get:
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%28x%2B%285%2F2%29%29%5E2+=+%28-22%2F4%29%2B%2825%2F4%29
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The right side combines to give:
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%28x%2B%285%2F2%29%29%5E2+=+3%2F4
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Now take the square root of both sides to get:
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x+%2B+%285%2F2%29+=+sqrt%283%2F4%29
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Note that when you take the square root of the right side, the square root is preceded by
both a + and a - sign. This shows in the next step. Look carefully for the two signs
between the two terms on the right side.
.
Subtract 5%2F2 from both sides and also transform the square root of 3/4 into the
square root of 3 divided by the square root of 4. When you do that you will get:
.
+x+=+-5%2F2+%2B-+sqrt%283%2F4%29+=+-5%2F2+%2B-+sqrt%283%29%2Fsqrt%284%29
.
The square root of 4 is 2 and when this is substituted the equation becomes:
.
x+=+-5%2F2+%2B-+sqrt%283%29%2F2
.
Hope this helps you to understand the process of completing the square to solve a quadratic
equation.