SOLUTION: There are five thieves, each loot a shop one after the other such that the first one takes 1/2 of the total no. of the Chocolates plus 1/2 of a Chocolate. Similarly 2nd, 3rd,4th a
Algebra ->
Inequalities
-> SOLUTION: There are five thieves, each loot a shop one after the other such that the first one takes 1/2 of the total no. of the Chocolates plus 1/2 of a Chocolate. Similarly 2nd, 3rd,4th a
Log On
Question 844041: There are five thieves, each loot a shop one after the other such that the first one takes 1/2 of the total no. of the Chocolates plus 1/2 of a Chocolate. Similarly 2nd, 3rd,4th and 5th also did the same. After the fifth one no. of Chocolates remained are 3. Initially how many Chocolates were there? Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let = the initial number of chocolates
-----------------
The 1st thief takes , so
there are left
--------------------------
The 2nd thief takes
There is left left
---------------------------
The 3rd thief takes
There is left left
---------------------------
The 4th thief takes
There is left left
----------------------------
The 5th thief takes
There is left left
-----------------------------
given:
------------------------------
There were 127 chocolates initially
check answer:
--------------------------------
1st thief takes
There are left
--------------------------------
2nd thief takes
There are left
--------------------------------
3rd thief takes
There are left
--------------------------------
4th thief takes
There are left
--------------------------------
5th thief takes
There are left
OK