SOLUTION: How many liters of 10% acid solution should be added to 20 liters of 60% solution of acid to obtain a 50% solution?
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Question 843988: How many liters of 10% acid solution should be added to 20 liters of 60% solution of acid to obtain a 50% solution? Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! .1x+.6*20=(20+x)*.5
x/10+3/5*20=10+x/2
x/10+12=10+x/2
x/10+2=x/2
x/10+2=5x/10
2=4x/10
20=4x
5=x
check
.5+12=25/2
12.5-=12.5
ok
