SOLUTION: If 100 = x(a) + y(b) + z(c)
x = 1
y = 5
z = .05
100 = 1(a) + 5(b) + .05(c)
Then what is the value of a,b and c?
Algebra ->
Absolute-value
-> SOLUTION: If 100 = x(a) + y(b) + z(c)
x = 1
y = 5
z = .05
100 = 1(a) + 5(b) + .05(c)
Then what is the value of a,b and c?
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Question 843957: If 100 = x(a) + y(b) + z(c)
x = 1
y = 5
z = .05
100 = 1(a) + 5(b) + .05(c)
Then what is the value of a,b and c? Answer by Fombitz(32388) (Show Source):
