Question 843889: A father is twice as old as his son. Twelve years ago the father was four times as old as the son was then. Determine their present age Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! A father is twice as old as his son. Twelve years ago the father was four times as old as the son was then. Determine their present age.
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let x=son's present age
2x=father's present age
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12 years ago:
x-12=son's age
2x-12= father's age
2x-12=4(x-12)
2x-12=4x-48
2x=36
x=18
2x=36
son's present age=18
father's present age=36
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