SOLUTION: Joe mixed raisins and nuts. He bought 4 pounds of nuts for a total of $22. The cost per pound of raisins is 60% more than the cost per pound for nuts. Joe bought enough raisins

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Question 843829: Joe mixed raisins and nuts. He bought 4 pounds of nuts for a total of $22. The cost per pound of raisins is 60% more than the cost per pound for nuts. Joe bought enough raisins that when he mixed them with the nuts, the mixture had a value of $6.50 per pound. What percent of the mixture, by weight, was raisins?
Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
Price of the nuts:
22 dollars for 4 pounds.
22%2F4 dollars per pound,
%2822%2F4%29%2825%2F25%29=550%2F100 dollars per pound
5.50 dollars per pound, nuts.
$5.50 per pound, nuts.

Price of the raisins:
This price is 60% higher than price of the nuts.
5.50%2B%280.60%29%285.50%29=%285.50%29%281.60%29=8.80
$8.80 per pound, raisins.


Mixture Price $6.50 Per Pound.
How much of each was used?
n for nuts
r for raisins.
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EQUATIONS: highlight_green%28n%2Br=100%29, which is arbitrary but convenient;
highlight_green%28%285.50n%2B8.80r%29%2F100=6.50%29.
Solve these two simultaneous equations for n and r.

Study this lesson to develop a thorough understanding of this type of mixture problem: http://www.algebra.com/tutors/mixture-price-two-part-both-parts-unknown.lesson?content_action=show_dev