SOLUTION: find the equation of the line that passes through (-1,-3) and (1,0) in standard form

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Question 843807: find the equation of the line that passes through (-1,-3) and (1,0) in standard form
Answer by 1335(25) About Me  (Show Source):
You can put this solution on YOUR website!
Use the slope formula: m=(y2-y1)/(x2-x1)
Plug your points into the formula: m=(0-(-3))/(1-(-1))
Simplify: m=0+3/1+1
Solve: m=3/2
Now use the point-slope formula: y-y1=m(x-x1)
Plug ONE of the given points for y1 and x1 ONLY.
y-0=3/2(x-1)
Multiply both sides by 2 to remove the fraction: 2y-0=3(x-1)
Simplify: 2y=3x-3
Subtract the 3x from both sides: -3x+2y=-3 (This answer is acceptable)
Divide by a negative 1: 3x-2y=3 (This answer is preferred) [Both answers are correct]