SOLUTION: What quantity of a 80% acid solution must be mixed with a 30% solution to produce 200 mL of a 45% solution?

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Question 843582: What quantity of a 80% acid solution must be mixed with a 30% solution to produce 200 mL of a 45% solution?
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
a+b=200,
.8a+.3b=.45*200
a=60, b=140