SOLUTION: Place in standard form and graph x^2+2x-4y^2+24y+10=0

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Question 843243: Place in standard form and graph x^2+2x-4y^2+24y+10=0
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Place in standard form and graph
x^2+2x-4y^2+24y+10=0
complete the square:
(x^2+2x+1)-4(y^2-6y+9)=-10+1-36
(x+1)^2-4(y-3)^2=-45
4(y-3)^2-(x+1)^2=45
%28y-3%29%5E2%2F%2845%2F4%29-%28x%2B1%29%5E2%2F45=1
This is an equation of a hyperbola with vertical transverse axis and center at (-1,3)
See graph below:
y=((45+(x+2)^2)^.5)/2+3