SOLUTION: How many gallons of a 90% antifreeze solution must be mixed with 90 gallons of 30% antifreeze to get a mixture that is 80% antifreeze?
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Question 843242: How many gallons of a 90% antifreeze solution must be mixed with 90 gallons of 30% antifreeze to get a mixture that is 80% antifreeze?
The word problem on this site that is exactly the same, gives a wrong answer of 480 gallons???? Answer by ewatrrr(24785) (Show Source):
Hi,
How many gallons of a 90% antifreeze solution must be mixed
with 90 gallons of 30% antifreeze to get a mixture that is 80% antifreeze?
.90x + .30(90gal) = .80(90gal + x)
x = .50(90gal)/.10 = 450gal