SOLUTION: A baker packed 32 doughnuts into 3 boxes. She put a different number of doughnuts into each box and there was an even amount in each box. How many doughnuts could there be in each

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Question 842476: A baker packed 32 doughnuts into 3 boxes. She put a different number of doughnuts into each box and there was an even amount in each box.
How many doughnuts could there be in each box?
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
32%2F2=16;
32%2F3=10%262%2F3;
32%2F4=8.

Three boxes must distribute these 32 doughnuts. .
Start with 10 and 12. That would be 22 doughnuts. Another with 8 will finish the 32. That is about the best way to distribute these 32 doughnuts.
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Boxes each for 8, 10, 12 doughnuts


ANOTHER TRY
16+12=28, and then third box to contain 4.
This is not as neat as the first described combination.

ANOTHER
14+12=26 and then third box to contain 6.
Still not as uniform as the first described combination.