SOLUTION: Need to see if I came up with the right answer to the following mixture problem: How much 5% acid must be added to 15% to get 50 ml of 8% acid? I ended up with 116 ml of 5% mus

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Question 842257: Need to see if I came up with the right answer to the following mixture problem: How much 5% acid must be added to 15% to get 50 ml of 8% acid?
I ended up with 116 ml of 5% must be added. Any Help

Found 2 solutions by richwmiller, Fombitz:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
How much 15% acid is there?
I will assume that the total amount will be 50 ml which means your number of 116 ml is way to high.
x+y=50
.05(x)+.15*y=.08*50
x=35., y=15.
if we start out with 15 ml of 15% and add 35 ml of 5% then we will get 50 ml of 8%



Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
First off, how can you add 116ml to come up with a 50ml volume?
So something is wrong.
Let X be the amount of 5% acid,Y be the amount of 15% acid.
Concentration:
5X%2B15Y=8%2850%29
1.X%2B3Y=80
Volume:
2.X%2BY=50
Subtract eq. 2 from eq. 1,
X%2B3Y-X-Y=80-50
2Y=30
Y=15
Then from eq. 2,
X%2B15=50
X=35