SOLUTION: OK, I have this " Let k(x)=-1/5x+3 . X when k(x)=-1 .. I came up with .2X but that is incorrect. What am I doing wrong? Do I fill in -1 for X? -1/5(-1)+3? Im thinking not becau

Algebra ->  College  -> Linear Algebra -> SOLUTION: OK, I have this " Let k(x)=-1/5x+3 . X when k(x)=-1 .. I came up with .2X but that is incorrect. What am I doing wrong? Do I fill in -1 for X? -1/5(-1)+3? Im thinking not becau      Log On


   

Question 842120: OK, I have this " Let k(x)=-1/5x+3 . X when k(x)=-1 .. I came up with .2X but that is incorrect. What am I doing wrong? Do I fill in -1 for X?
-1/5(-1)+3? Im thinking not because its out side of the parenthesis. Thank you
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

over thinking it...re reply:

k(x) = highlight%28%28-1%2F5%29x+%2B+3%29, k(x) = highlight%281%29

highlight%28%28-1%2F5%29x+%2B+3%29=  highlight%281%29

 x+=+20



highlight_green%28k%28x%29%29 = -1/5x + 3, highlight_green%28k%28x%29%29 = -1 ⇒



 -1/5x + 3 = -1

   -1/5x = -4

       x = 20

Wish You the Best in your Studies.