SOLUTION: Tina's calculations of the tarantula stated that it was able to cover 20 cm. in 5 sec. What is the average speed of the spider in m/s

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Question 842102: Tina's calculations of the tarantula stated that it was able to cover 20 cm. in 5 sec. What is the average speed of the spider in m/s
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
20 cm = 20/100 = 0.20 meters

(20 cm)/(5 sec) = (0.20 meters)/(5 seconds)

(20 cm)/(5 sec) = 0.04 meters per second