SOLUTION: 1. An art dealer sold two artworks for $1520 thereby making a profit of 25% on the first work and 10% profit on the other, whereas if he had approached any exhibition he would have

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: 1. An art dealer sold two artworks for $1520 thereby making a profit of 25% on the first work and 10% profit on the other, whereas if he had approached any exhibition he would have      Log On


   

Question 84207: 1. An art dealer sold two artworks for $1520 thereby making a profit of 25% on the first work and 10% profit on the other, whereas if he had approached any exhibition he would have sold them together for $1535 with a profit of 10% on the first and 25% on the other artwork. Find the actual cost of each artwork.
Answer by PS(13) About Me  (Show Source):
You can put this solution on YOUR website!
Assume first work costs x and second work costs y
Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
We'll use substitution. After moving 1.1*y to the right, we get:
1.25%2Ax+=+1520+-+1.1%2Ay, or x+=+1520%2F1.25+-+1.1%2Ay%2F1.25. Substitute that
into another equation:
1.1%2A%281520%2F1.25+-+1.1%2Ay%2F1.25%29+%2B+1.25%5Cy+=+1535 and simplify: So, we know that y=700. Since x+=+1520%2F1.25+-+1.1%2Ay%2F1.25, x=600.

Answer: system%28+x=600%2C+y=700+%29.


So, the first artwork costs 600 and the second artwork costs 700