SOLUTION: 2y^2+4xy=x^2 Solve for y. The book says the answer is y=x(-1+or- sqrt 6/2) I can't get to the answer please help!

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Question 842043: 2y^2+4xy=x^2
Solve for y.
The book says the answer is y=x(-1+or- sqrt 6/2)
I can't get to the answer please help!
Answer by josgarithmetic(39631) About Me  (Show Source):