SOLUTION: Two marbles are drawn randomly one after the other without replacement from a jar that contains 6 red marbles, 8 white marbles, and 2 yellow marbles. Find the probability of the fo

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Question 842040: Two marbles are drawn randomly one after the other without replacement from a jar that contains 6 red marbles, 8 white marbles, and 2 yellow marbles. Find the probability of the following events. What is the probability that a yellow marble will not be chosen at all?
Found 2 solutions by Fombitz, stanbon:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!

Without choosing yellow the possible choices are
RR: %286%2F16%29%285%2F15%29=%283%2F8%29%281%2F5%29=3%2F40
WW: %288%2F16%29%287%2F15%29=%281%2F2%29%287%2F15%29=7%2F30
RW: %286%2F16%29%285%2F15%29=%283%2F8%29%281%2F3%29=1%2F8
WR: %288%2F16%29%286%2F15%29=%281%2F2%29%282%2F5%29=1%2F5
So then the probabilities add to,
P=3%2F40%2B7%2F30%2B1%2F8%2B1%2F5=9%2F120%2B28%2F120%2B15%2F120%2B24%2F120=76%2F120=19%2F30

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Probability-and-statistics/842040 (2014-02-16 21:54:24): Two marbles are drawn randomly one after the other without replacement from a jar that contains 6 red marbles, 8 white marbles, and 2 yellow marbles. Find the probability of the following events. What is the probability that a yellow marble will not be chosen at all?
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# of ways to succeed::: 14C2 = 91
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# of random pairs::: 16C2 = 120
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Ans:: 91/120
Cheers.
Stan H.