Question 841909: Determine how many four-character codes can be formed if the first character is a nonzero digit, the second character is any digit, and the third and fourth characters are uppercase letters of the alphabet, and repetition of digits and letters is allowed.
(A digit is 0, 1, 2, .., or 9.) Work optional. 1. ______
A. 71
B. 988
C. 52,650
D. 60,840
Suppose that a multiple choice exam has five questions and each question has four choices. In how many ways can the exam be completed? Work optional. 2. __B____
A. 1,024
B. 625
C. 120
D. 20
Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website!
Hi,
how many four-character codes can be formed if the first character is a nonzero digit,
the second character is any digit, and the third and fourth characters are uppercase letters of the alphabet,
and repetition of digits and letters is allowed.
9*10*26*26
multiple choice exam has five questions and each question has four choices:
In how many ways can the exam be completed? 4^5
|
|
|