SOLUTION: an interval containing one period of y=3tan(x-Pie(3.24)/(over)3. Thus 2 consecutive asymptotes occur at x=????
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Question 841896: an interval containing one period of y=3tan(x-Pie(3.24)/(over)3. Thus 2 consecutive asymptotes occur at x=???? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! an interval containing one period of y=3tan(x-Pie(3.24)/(over)3. Thus 2 consecutive asymptotes occur at x=????
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consecutive asymptotes for the tangent occur at -pi/2 and at pi/2
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Solve: x-pi/3 = -pi/2 and x-pi/3 = pi/2
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x = -(pi/2)+(pi/3) and x = (pi/2) + (pi/3)
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x = (-3pi+2pi)/6 and x = (3pi+2pi)/6
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x = -pi/6 and x = (5/6)pi
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Cheers,
stan H.
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