SOLUTION: 1-2cos^2x=(tan^2x-1)/(tan^2x+1)
i need help with this equation. i need to have it in a t-table format. can you please help me?!
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-> SOLUTION: 1-2cos^2x=(tan^2x-1)/(tan^2x+1)
i need help with this equation. i need to have it in a t-table format. can you please help me?!
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Question 841860: 1-2cos^2x=(tan^2x-1)/(tan^2x+1)
i need help with this equation. i need to have it in a t-table format. can you please help me?! Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 1-2cos^2x=(tan^2x-1)/(tan^2x+1)
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(1-cos^2(x)-cos^2(x) = (tan^2(x)-1)/sec^2(x)
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sin^2(x)-cos^2(x) = (tan^2(x)-1)/sec^2(x)
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Cross-multiply to get:
sin^2(x)*sec^2(x) - 1 = tan^2(x)-1
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sin^2(x)/cos^2(x) - 1 = tan^2(x)-1
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tan^2(x)-1 = tan^2(x)-1
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Cheers,
Stan H.
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